8.Electromagnetic waves
hard

A plane electromagnetic wave in a non-magnetic dielectric medium is given by $\vec E\, = \,{\vec E_0}\,(4 \times {10^{ - 7}}\,x - 50t)$ with distance being in meter and time in seconds. The dielectric constant of the medium is

A

$2.4$

B

$5.8$

C

$8.2$

D

$4.8$

(JEE MAIN-2013)

Solution

Given equation of wave

$\vec{E}=\vec{E}_{0}(4 \times \overrightarrow{10} x-50 t)$

Comparing with general equation of wave,

$\vec{E}=\vec{E}_{0}(k x-w t)$

we get,

$w=50$ rad $/ s . k=4 \times 10^{-7} m^{-1}$

Thus velocity of wave,

$v=\frac{w}{k}=\frac{50}{4 \times 10^{-7}}=1.25 \times 10^{8} \mathrm{m} / \mathrm{s}$

so, refractive index of medium,

$\mu=\frac{e}{v}=\frac{3 \times 10^{8}}{1.25 \times 10^{8}}=2.4$

using, $u^{2}=k m . k e[\mathrm{km}$ and ke are magnetic and dielectric di – constants]

as medium is non diamagnetic, $k m=1$

$\Rightarrow k e=\mu^{2}=(2.4)^{2} \Rightarrow k e=5.76$

Standard 12
Physics

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